Java合并流并保留唯一元素
合并数字和字符串流
在合并两个流时,我们可以使用 distinct() API,结果流将只包含唯一的元素。
import java.util.stream.Collectors; import java.util.stream.Stream; public class Main { public static void main(String[] args) { Stream<Integer> firstStream = Stream.of(1, 2, 3, 4, 5, 6); Stream<Integer> secondStream = Stream.of(4, 5, 6, 7, 8, 9); Stream<Integer> resultingStream = Stream.concat(firstStream, secondStream) .distinct(); System.out.println( resultingStream.collect(Collectors.toList()) ); } }
Java 合并自定义对象流
在合并自定义对象流的情况下,我们可以在流迭代期间删除重复的元素。
我们可以使用为 java 流创建的 distinctByKey() 函数根据对象的属性进行区分。
import java.util.ArrayList; import java.util.Map; import java.util.concurrent.ConcurrentHashMap; import java.util.function.Function; import java.util.function.Predicate; import java.util.stream.Collectors; import java.util.stream.Stream; public class Main { public static void main(String[] args) { Stream<Employee> stream1 = getEmployeeListOne().stream(); Stream<Employee> stream2 = getEmployeeListTwo().stream(); Stream<Employee> resultingStream = Stream.concat(stream1, stream2) .filter(distinctByKey(Employee::getFirstName)); System.out.println( resultingStream.collect(Collectors.toList()) ); } public static <T> Predicate<T> distinctByKey(Function<? super T, Object> keyExtractor) { Map<Object, Boolean> map = new ConcurrentHashMap<>(); return t -> map.putIfAbsent(keyExtractor.apply(t), Boolean.TRUE) == null; } private static ArrayList<Employee> getEmployeeListOne() { ArrayList<Employee> list = new ArrayList<>(); list.add( new Employee(1l, "JackLi", "Gupta") ); list.add( new Employee(5l, "BobRobert", "Piper") ); list.add( new Employee(7l, "Lucie", "Piper") ); list.add( new Employee(6l, "Tomm", "Beckham") ); return list; } private static ArrayList<Employee> getEmployeeListTwo() { ArrayList<Employee> list = new ArrayList<>(); list.add( new Employee(2l, "JackLi", "Gupta") ); list.add( new Employee(4l, "BobRobert", "Piper") ); list.add( new Employee(3l, "Tomm", "Beckham") ); return list; } }
用 Stream.concat() 方法用于将两个流合并为一个流,该流由两个被合并流的所有元素组成。
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Java合并多个流 示例
import java.util.stream.Collectors; import java.util.stream.Stream; import static java.util.stream.Stream.*; public class Main { public static void main(String[] args) { Stream<Integer> first = Stream.of(1, 2); Stream<Integer> second = Stream.of(3,4); Stream<Integer> third = Stream.of(5, 6); Stream<Integer> fourth = Stream.of(7,8); Stream<Integer> resultingStream = Stream.concat(first, concat(second, concat(third, fourth))); System.out.println( resultingStream.collect(Collectors.toList()) ); } }
Java 合并两个流示例
import java.util.stream.Stream; public class Main { public static void main(String[] args) { Stream<Integer> firstStream = Stream.of(1, 2, 3); Stream<Integer> secondStream = Stream.of(4, 5, 6); Stream<Integer> resultingStream = Stream.concat(firstStream, secondStream); System.out.println( resultingStream.collect(Collectors.toList()) ); } }
Stream concat()方法
static <T> Stream<T> concat(Stream<? extends T> firstStream, Stream<? extends T> secondStream)
- 此方法创建一个延迟连接的流,其元素是 firstStream 的所有元素,后跟 secondStream 的所有元素。
- 如果两个输入流都是有序的,则结果流是有序的。
- 如果任一输入流是并行的,则结果流是并行的。
- 当结果流被关闭时,两个输入流的关闭处理程序都会被调用。
日期:2020-09-17 00:10:04 来源:oir作者:oir