解决方案

Select
Name,
Count(Name) As Count
From
Table
Group By
Name
Having
Count(Name) > 1
Order By
Count(Name) Desc

这也可以扩展为删除重复项：

Delete
From
Table
Where
Key In (
    Select
    Max(Key)
    From
    Table
    Group By
    Name
    Having
Count(Name) > 1)

还可以通过将表与其自身连接来实现，

SELECT DISTINCT t1.name
FROM    tbl t1
        INNER JOIN tbl t2
        ON      t1.name = t2.name
WHERE   t1.key         != t2.key;

假设有这样的数据：

+---+----+
|Key|Name|
+---+----+
|1  |Dan |
+---+----+
|2  |Tom |
+---+----+
|3  |Jon |
+---+----+
|4  |Tom |
+---+----+
|5  |Sam |
+---+----+
|6  |Dan |
+---+----+

如何查询Name出现两次以上的结果？

比如，Tom 和Dan出现两次

+---+
 |Tom|
 +---+
 |Dan|
 +---+